7(k-6)+42=2(4K+5)

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Solution for 7(k-6)+42=2(4K+5) equation: 



7(k-6)+42=2(4+5)

We move all terms to the left:

7(k-6)+42-(2(4+5))=0

We add all the numbers together, and all the variables

7(k-6)+42-(29)=0

We add all the numbers together, and all the variables

7(k-6)+13=0

We multiply parentheses

7k-42+13=0

We add all the numbers together, and all the variables

7k-29=0

We move all terms containing k to the left, all other terms to the right

7k=29

k=29/7

k=4+1/7

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