7(k-4)+10=3k+20+4k-2

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Solution for 7(k-4)+10=3k+20+4k-2 equation:


Simplifying
7(k + -4) + 10 = 3k + 20 + 4k + -2

Reorder the terms:
7(-4 + k) + 10 = 3k + 20 + 4k + -2
(-4 * 7 + k * 7) + 10 = 3k + 20 + 4k + -2
(-28 + 7k) + 10 = 3k + 20 + 4k + -2

Reorder the terms:
-28 + 10 + 7k = 3k + 20 + 4k + -2

Combine like terms: -28 + 10 = -18
-18 + 7k = 3k + 20 + 4k + -2

Reorder the terms:
-18 + 7k = 20 + -2 + 3k + 4k

Combine like terms: 20 + -2 = 18
-18 + 7k = 18 + 3k + 4k

Combine like terms: 3k + 4k = 7k
-18 + 7k = 18 + 7k

Add '-7k' to each side of the equation.
-18 + 7k + -7k = 18 + 7k + -7k

Combine like terms: 7k + -7k = 0
-18 + 0 = 18 + 7k + -7k
-18 = 18 + 7k + -7k

Combine like terms: 7k + -7k = 0
-18 = 18 + 0
-18 = 18

Solving
-18 = 18

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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