7(k-3)-2(2k+4)=10

Solution for 7(k-3)-2(2k+4)=10 equation:

Simplifying
7(k + -3) + -2(2k + 4) = 10

Reorder the terms:
7(-3 + k) + -2(2k + 4) = 10
(-3 * 7 + k * 7) + -2(2k + 4) = 10
(-21 + 7k) + -2(2k + 4) = 10

Reorder the terms:
-21 + 7k + -2(4 + 2k) = 10
-21 + 7k + (4 * -2 + 2k * -2) = 10
-21 + 7k + (-8 + -4k) = 10

Reorder the terms:
-21 + -8 + 7k + -4k = 10

Combine like terms: -21 + -8 = -29
-29 + 7k + -4k = 10

Combine like terms: 7k + -4k = 3k
-29 + 3k = 10

Solving
-29 + 3k = 10

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '29' to each side of the equation.
-29 + 29 + 3k = 10 + 29

Combine like terms: -29 + 29 = 0
0 + 3k = 10 + 29
3k = 10 + 29

Combine like terms: 10 + 29 = 39
3k = 39

Divide each side by '3'.
k = 13

Simplifying
k = 13