7(k-12)=3(k5-12)

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Solution for 7(k-12)=3(k5-12) equation: 



7(k-12)=3(k5-12)

We move all terms to the left:

7(k-12)-(3(k5-12))=0

We add all the numbers together, and all the variables

-(3(+k^5-12))+7(k-12)=0

We multiply parentheses

-(3(+k^5-12))+7k-84=0



We calculate terms in parentheses: -(3(+k^5-12)), so:

3(+k^5-12)

We do not support ekpression: k^5

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