7(f+3)+9=5(f-2)-3f

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Solution for 7(f+3)+9=5(f-2)-3f equation: 



7(f+3)+9=5(f-2)-3f

We move all terms to the left:

7(f+3)+9-(5(f-2)-3f)=0

We multiply parentheses

7f-(5(f-2)-3f)+21+9=0



We calculate terms in parentheses: -(5(f-2)-3f), so:

5(f-2)-3f

We add all the numbers together, and all the variables

-3f+5(f-2)

We multiply parentheses

-3f+5f-10

We add all the numbers together, and all the variables

2f-10

Back to the equation:

-(2f-10)



We add all the numbers together, and all the variables

7f-(2f-10)+30=0

We get rid of parentheses

7f-2f+10+30=0

We add all the numbers together, and all the variables

5f+40=0

We move all terms containing f to the left, all other terms to the right

5f=-40

f=-40/5

f=-8

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