7(d-2)=5(d+2)+6d

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Solution for 7(d-2)=5(d+2)+6d equation: 



7(d-2)=5(d+2)+6d

We move all terms to the left:

7(d-2)-(5(d+2)+6d)=0

We multiply parentheses

7d-(5(d+2)+6d)-14=0



We calculate terms in parentheses: -(5(d+2)+6d), so:

5(d+2)+6d

We add all the numbers together, and all the variables

6d+5(d+2)

We multiply parentheses

6d+5d+10

We add all the numbers together, and all the variables

11d+10

Back to the equation:

-(11d+10)



We get rid of parentheses

7d-11d-10-14=0

We add all the numbers together, and all the variables

-4d-24=0

We move all terms containing d to the left, all other terms to the right

-4d=24

d=24/-4

d=-6

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