7(d-2)-3d=5-2(d+3)+4

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Solution for 7(d-2)-3d=5-2(d+3)+4 equation: 



7(d-2)-3d=5-2(d+3)+4

We move all terms to the left:

7(d-2)-3d-(5-2(d+3)+4)=0

We add all the numbers together, and all the variables

-3d+7(d-2)-(5-2(d+3)+4)=0

We multiply parentheses

-3d+7d-(5-2(d+3)+4)-14=0



We calculate terms in parentheses: -(5-2(d+3)+4), so:

5-2(d+3)+4

determiningTheFunctionDomain
-2(d+3)+5+4

We add all the numbers together, and all the variables

-2(d+3)+9

We multiply parentheses

-2d-6+9

We add all the numbers together, and all the variables

-2d+3

Back to the equation:

-(-2d+3)



We add all the numbers together, and all the variables

4d-(-2d+3)-14=0

We get rid of parentheses

4d+2d-3-14=0

We add all the numbers together, and all the variables

6d-17=0

We move all terms containing d to the left, all other terms to the right

6d=17

d=17/6

d=2+5/6

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