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7(c-5)=2(c+5)
We move all terms to the left:
7(c-5)-(2(c+5))=0
We multiply parentheses
7c-(2(c+5))-35=0
We calculate terms in parentheses: -(2(c+5)), so:We get rid of parentheses
2(c+5)
We multiply parentheses
2c+10
Back to the equation:
-(2c+10)
7c-2c-10-35=0
We add all the numbers together, and all the variables
5c-45=0
We move all terms containing c to the left, all other terms to the right
5c=45
c=45/5
c=9
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