7(c-4)+3=2+c-27

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Solution for 7(c-4)+3=2+c-27 equation: 


Simplifying
7(c + -4) + 3 = 2 + c + -27

Reorder the terms:
7(-4 + c) + 3 = 2 + c + -27
(-4 * 7 + c * 7) + 3 = 2 + c + -27
(-28 + 7c) + 3 = 2 + c + -27

Reorder the terms:
-28 + 3 + 7c = 2 + c + -27

Combine like terms: -28 + 3 = -25
-25 + 7c = 2 + c + -27

Reorder the terms:
-25 + 7c = 2 + -27 + c

Combine like terms: 2 + -27 = -25
-25 + 7c = -25 + c

Add '25' to each side of the equation.
-25 + 25 + 7c = -25 + 25 + c

Combine like terms: -25 + 25 = 0
0 + 7c = -25 + 25 + c
7c = -25 + 25 + c

Combine like terms: -25 + 25 = 0
7c = 0 + c
7c = c

Solving
7c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
7c + -1c = c + -1c

Combine like terms: 7c + -1c = 6c
6c = c + -1c

Combine like terms: c + -1c = 0
6c = 0

Divide each side by '6'.
c = 0

Simplifying
c = 0

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