7(c-3)=8(c-6)

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Solution for 7(c-3)=8(c-6) equation: 



7(c-3)=8(c-6)

We move all terms to the left:

7(c-3)-(8(c-6))=0

We multiply parentheses

7c-(8(c-6))-21=0



We calculate terms in parentheses: -(8(c-6)), so:

8(c-6)

We multiply parentheses

8c-48

Back to the equation:

-(8c-48)



We get rid of parentheses

7c-8c+48-21=0

We add all the numbers together, and all the variables

-1c+27=0

We move all terms containing c to the left, all other terms to the right

-c=-27

c=-27/-1

c=+27

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