7(c+1)=6c-8

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Solution for 7(c+1)=6c-8 equation:


Simplifying
7(c + 1) = 6c + -8

Reorder the terms:
7(1 + c) = 6c + -8
(1 * 7 + c * 7) = 6c + -8
(7 + 7c) = 6c + -8

Reorder the terms:
7 + 7c = -8 + 6c

Solving
7 + 7c = -8 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
7 + 7c + -6c = -8 + 6c + -6c

Combine like terms: 7c + -6c = 1c
7 + 1c = -8 + 6c + -6c

Combine like terms: 6c + -6c = 0
7 + 1c = -8 + 0
7 + 1c = -8

Add '-7' to each side of the equation.
7 + -7 + 1c = -8 + -7

Combine like terms: 7 + -7 = 0
0 + 1c = -8 + -7
1c = -8 + -7

Combine like terms: -8 + -7 = -15
1c = -15

Divide each side by '1'.
c = -15

Simplifying
c = -15

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