7(b-1)-4b=3(b+5)

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Solution for 7(b-1)-4b=3(b+5) equation: 



7(b-1)-4b=3(b+5)

We move all terms to the left:

7(b-1)-4b-(3(b+5))=0

We add all the numbers together, and all the variables

-4b+7(b-1)-(3(b+5))=0

We multiply parentheses

-4b+7b-(3(b+5))-7=0



We calculate terms in parentheses: -(3(b+5)), so:

3(b+5)

We multiply parentheses

3b+15

Back to the equation:

-(3b+15)



We add all the numbers together, and all the variables

3b-(3b+15)-7=0

We get rid of parentheses

3b-3b-15-7=0

We add all the numbers together, and all the variables

-22!=0

There is no solution for this equation

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