7(b+3)=2(5b+3)

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Solution for 7(b+3)=2(5b+3) equation: 



7(b+3)=2(5b+3)

We move all terms to the left:

7(b+3)-(2(5b+3))=0

We multiply parentheses

7b-(2(5b+3))+21=0



We calculate terms in parentheses: -(2(5b+3)), so:

2(5b+3)

We multiply parentheses

10b+6

Back to the equation:

-(10b+6)



We get rid of parentheses

7b-10b-6+21=0

We add all the numbers together, and all the variables

-3b+15=0

We move all terms containing b to the left, all other terms to the right

-3b=-15

b=-15/-3

b=+5

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