7(b+2)=5(b-6)+12(b+5)

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Solution for 7(b+2)=5(b-6)+12(b+5) equation: 



7(b+2)=5(b-6)+12(b+5)

We move all terms to the left:

7(b+2)-(5(b-6)+12(b+5))=0

We multiply parentheses

7b-(5(b-6)+12(b+5))+14=0



We calculate terms in parentheses: -(5(b-6)+12(b+5)), so:

5(b-6)+12(b+5)

We multiply parentheses

5b+12b-30+60

We add all the numbers together, and all the variables

17b+30

Back to the equation:

-(17b+30)



We get rid of parentheses

7b-17b-30+14=0

We add all the numbers together, and all the variables

-10b-16=0

We move all terms containing b to the left, all other terms to the right

-10b=16

b=16/-10

b=-1+3/5

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