7(a-7)+14=3(a-5)

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Solution for 7(a-7)+14=3(a-5) equation:


Simplifying
7(a + -7) + 14 = 3(a + -5)

Reorder the terms:
7(-7 + a) + 14 = 3(a + -5)
(-7 * 7 + a * 7) + 14 = 3(a + -5)
(-49 + 7a) + 14 = 3(a + -5)

Reorder the terms:
-49 + 14 + 7a = 3(a + -5)

Combine like terms: -49 + 14 = -35
-35 + 7a = 3(a + -5)

Reorder the terms:
-35 + 7a = 3(-5 + a)
-35 + 7a = (-5 * 3 + a * 3)
-35 + 7a = (-15 + 3a)

Solving
-35 + 7a = -15 + 3a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-3a' to each side of the equation.
-35 + 7a + -3a = -15 + 3a + -3a

Combine like terms: 7a + -3a = 4a
-35 + 4a = -15 + 3a + -3a

Combine like terms: 3a + -3a = 0
-35 + 4a = -15 + 0
-35 + 4a = -15

Add '35' to each side of the equation.
-35 + 35 + 4a = -15 + 35

Combine like terms: -35 + 35 = 0
0 + 4a = -15 + 35
4a = -15 + 35

Combine like terms: -15 + 35 = 20
4a = 20

Divide each side by '4'.
a = 5

Simplifying
a = 5

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