7(a-6)+14=4(a-4)

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Solution for 7(a-6)+14=4(a-4) equation: 



7(a-6)+14=4(a-4)

We move all terms to the left:

7(a-6)+14-(4(a-4))=0

We multiply parentheses

7a-(4(a-4))-42+14=0



We calculate terms in parentheses: -(4(a-4)), so:

4(a-4)

We multiply parentheses

4a-16

Back to the equation:

-(4a-16)



We add all the numbers together, and all the variables

7a-(4a-16)-28=0

We get rid of parentheses

7a-4a+16-28=0

We add all the numbers together, and all the variables

3a-12=0

We move all terms containing a to the left, all other terms to the right

3a=12

a=12/3

a=4

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