7(a-5)+10=3(a+1)

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Solution for 7(a-5)+10=3(a+1) equation: 



7(a-5)+10=3(a+1)

We move all terms to the left:

7(a-5)+10-(3(a+1))=0

We multiply parentheses

7a-(3(a+1))-35+10=0



We calculate terms in parentheses: -(3(a+1)), so:

3(a+1)

We multiply parentheses

3a+3

Back to the equation:

-(3a+3)



We add all the numbers together, and all the variables

7a-(3a+3)-25=0

We get rid of parentheses

7a-3a-3-25=0

We add all the numbers together, and all the variables

4a-28=0

We move all terms containing a to the left, all other terms to the right

4a=28

a=28/4

a=7

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