7(a-2)+5(a-4)=12a

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Solution for 7(a-2)+5(a-4)=12a equation:


Simplifying
7(a + -2) + 5(a + -4) = 12a

Reorder the terms:
7(-2 + a) + 5(a + -4) = 12a
(-2 * 7 + a * 7) + 5(a + -4) = 12a
(-14 + 7a) + 5(a + -4) = 12a

Reorder the terms:
-14 + 7a + 5(-4 + a) = 12a
-14 + 7a + (-4 * 5 + a * 5) = 12a
-14 + 7a + (-20 + 5a) = 12a

Reorder the terms:
-14 + -20 + 7a + 5a = 12a

Combine like terms: -14 + -20 = -34
-34 + 7a + 5a = 12a

Combine like terms: 7a + 5a = 12a
-34 + 12a = 12a

Add '-12a' to each side of the equation.
-34 + 12a + -12a = 12a + -12a

Combine like terms: 12a + -12a = 0
-34 + 0 = 12a + -12a
-34 = 12a + -12a

Combine like terms: 12a + -12a = 0
-34 = 0

Solving
-34 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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