7(9x-2)+3=-3(4x+1)+6

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Solution for 7(9x-2)+3=-3(4x+1)+6 equation: 



7(9x-2)+3=-3(4x+1)+6

We move all terms to the left:

7(9x-2)+3-(-3(4x+1)+6)=0

We multiply parentheses

63x-(-3(4x+1)+6)-14+3=0



We calculate terms in parentheses: -(-3(4x+1)+6), so:

-3(4x+1)+6

We multiply parentheses

-12x-3+6

We add all the numbers together, and all the variables

-12x+3

Back to the equation:

-(-12x+3)



We add all the numbers together, and all the variables

63x-(-12x+3)-11=0

We get rid of parentheses

63x+12x-3-11=0

We add all the numbers together, and all the variables

75x-14=0

We move all terms containing x to the left, all other terms to the right

75x=14

x=14/75

x=14/75

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