7(8x+5)-35=4(1+14x)-4

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Solution for 7(8x+5)-35=4(1+14x)-4 equation: 



7(8x+5)-35=4(1+14x)-4

We move all terms to the left:

7(8x+5)-35-(4(1+14x)-4)=0

We add all the numbers together, and all the variables

7(8x+5)-(4(14x+1)-4)-35=0

We multiply parentheses

56x-(4(14x+1)-4)+35-35=0



We calculate terms in parentheses: -(4(14x+1)-4), so:

4(14x+1)-4

We multiply parentheses

56x+4-4

We add all the numbers together, and all the variables

56x

Back to the equation:

-(56x)



We add all the numbers together, and all the variables

=0

x=0/1

x=0

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