7(7x+5)=41x-3

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Solution for 7(7x+5)=41x-3 equation: 



7(7x+5)=41x-3

We move all terms to the left:

7(7x+5)-(41x-3)=0

We multiply parentheses

49x-(41x-3)+35=0

We get rid of parentheses

49x-41x+3+35=0

We add all the numbers together, and all the variables

8x+38=0

We move all terms containing x to the left, all other terms to the right

8x=-38

x=-38/8

x=-4+3/4

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