7(7x+3)=3(3x+5)+166

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Solution for 7(7x+3)=3(3x+5)+166 equation: 



7(7x+3)=3(3x+5)+166

We move all terms to the left:

7(7x+3)-(3(3x+5)+166)=0

We multiply parentheses

49x-(3(3x+5)+166)+21=0



We calculate terms in parentheses: -(3(3x+5)+166), so:

3(3x+5)+166

We multiply parentheses

9x+15+166

We add all the numbers together, and all the variables

9x+181

Back to the equation:

-(9x+181)



We get rid of parentheses

49x-9x-181+21=0

We add all the numbers together, and all the variables

40x-160=0

We move all terms containing x to the left, all other terms to the right

40x=160

x=160/40

x=4

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