7(7c+1)=15(c-4)

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Solution for 7(7c+1)=15(c-4) equation:



7(7c+1)=15(c-4)
We move all terms to the left:
7(7c+1)-(15(c-4))=0
We multiply parentheses
49c-(15(c-4))+7=0
We calculate terms in parentheses: -(15(c-4)), so:
15(c-4)
We multiply parentheses
15c-60
Back to the equation:
-(15c-60)
We get rid of parentheses
49c-15c+60+7=0
We add all the numbers together, and all the variables
34c+67=0
We move all terms containing c to the left, all other terms to the right
34c=-67
c=-67/34
c=-1+33/34

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