7(7c+1)-4c=13(3c-21

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Solution for 7(7c+1)-4c=13(3c-21 equation: 



7(7c+1)-4c=13(3c-21

We move all terms to the left:

7(7c+1)-4c-(13(3c-21)=0

We add all the numbers together, and all the variables

-4c+7(7c+1)-(13(3c-21)=0

We multiply parentheses

-4c+49c-(13(3c-21)+7=0

We add all the numbers together, and all the variables

45c-(13(3c-21)+7=0

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