7(7+(y+3))=8(8+y)

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Solution for 7(7+(y+3))=8(8+y) equation: 



7(7+(y+3))=8(8+y)

We move all terms to the left:

7(7+(y+3))-(8(8+y))=0

We add all the numbers together, and all the variables

7(7+(y+3))-(8(y+8))=0



We calculate terms in parentheses: -(8(y+8)), so:

8(y+8)

We multiply parentheses

8y+64

Back to the equation:

-(8y+64)



We get rid of parentheses

7(7+(y+3))-8y-64=0

We add all the numbers together, and all the variables

-8y+7(7+(y+3))-64=0

We move all terms containing y to the left, all other terms to the right

-8y+7(7+(y+3))=64

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