7(6x-5)-4(3x-2)=1

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Solution for 7(6x-5)-4(3x-2)=1 equation: 



7(6x-5)-4(3x-2)=1

We move all terms to the left:

7(6x-5)-4(3x-2)-(1)=0

We multiply parentheses

42x-12x-35+8-1=0

We add all the numbers together, and all the variables

30x-28=0

We move all terms containing x to the left, all other terms to the right

30x=28

x=28/30

x=14/15

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