7(6-x)=3(x-2)

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Solution for 7(6-x)=3(x-2) equation: 



7(6-x)=3(x-2)

We move all terms to the left:

7(6-x)-(3(x-2))=0

We add all the numbers together, and all the variables

7(-1x+6)-(3(x-2))=0

We multiply parentheses

-7x-(3(x-2))+42=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

-7x-3x+6+42=0

We add all the numbers together, and all the variables

-10x+48=0

We move all terms containing x to the left, all other terms to the right

-10x=-48

x=-48/-10

x=4+4/5

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