7(6-2r)=5(-3r+1)

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Solution for 7(6-2r)=5(-3r+1) equation: 



7(6-2r)=5(-3r+1)

We move all terms to the left:

7(6-2r)-(5(-3r+1))=0

We add all the numbers together, and all the variables

7(-2r+6)-(5(-3r+1))=0

We multiply parentheses

-14r-(5(-3r+1))+42=0



We calculate terms in parentheses: -(5(-3r+1)), so:

5(-3r+1)

We multiply parentheses

-15r+5

Back to the equation:

-(-15r+5)



We get rid of parentheses

-14r+15r-5+42=0

We add all the numbers together, and all the variables

r+37=0

We move all terms containing r to the left, all other terms to the right

r=-37

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