7(6-2a)=4(3a+4)

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Solution for 7(6-2a)=4(3a+4) equation: 



7(6-2a)=4(3a+4)

We move all terms to the left:

7(6-2a)-(4(3a+4))=0

We add all the numbers together, and all the variables

7(-2a+6)-(4(3a+4))=0

We multiply parentheses

-14a-(4(3a+4))+42=0



We calculate terms in parentheses: -(4(3a+4)), so:

4(3a+4)

We multiply parentheses

12a+16

Back to the equation:

-(12a+16)



We get rid of parentheses

-14a-12a-16+42=0

We add all the numbers together, and all the variables

-26a+26=0

We move all terms containing a to the left, all other terms to the right

-26a=-26

a=-26/-26

a=1

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