7(6-12k)-3=-2k-5(11k+3)

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Solution for 7(6-12k)-3=-2k-5(11k+3) equation: 



7(6-12k)-3=-2k-5(11k+3)

We move all terms to the left:

7(6-12k)-3-(-2k-5(11k+3))=0

We add all the numbers together, and all the variables

7(-12k+6)-(-2k-5(11k+3))-3=0

We multiply parentheses

-84k-(-2k-5(11k+3))+42-3=0



We calculate terms in parentheses: -(-2k-5(11k+3)), so:

-2k-5(11k+3)

We multiply parentheses

-2k-55k-15

We add all the numbers together, and all the variables

-57k-15

Back to the equation:

-(-57k-15)



We add all the numbers together, and all the variables

-84k-(-57k-15)+39=0

We get rid of parentheses

-84k+57k+15+39=0

We add all the numbers together, and all the variables

-27k+54=0

We move all terms containing k to the left, all other terms to the right

-27k=-54

k=-54/-27

k=+2

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