7(6+c)=6(1+c)

Solution for 7(6+c)=6(1+c) equation:

7(6+c)=6(1+c)

We move all terms to the left:

7(6+c)-(6(1+c))=0

We add all the numbers together, and all the variables

7(c+6)-(6(c+1))=0

We multiply parentheses

7c-(6(c+1))+42=0


We calculate terms in parentheses: -(6(c+1)), so:

6(c+1)

We multiply parentheses

6c+6

Back to the equation:

-(6c+6)


We get rid of parentheses

7c-6c-6+42=0

We add all the numbers together, and all the variables

c+36=0

We move all terms containing c to the left, all other terms to the right

c=-36