7(5y-2)+6(2y+6)=25(3y+2)-12y

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Solution for 7(5y-2)+6(2y+6)=25(3y+2)-12y equation: 



7(5y-2)+6(2y+6)=25(3y+2)-12y

We move all terms to the left:

7(5y-2)+6(2y+6)-(25(3y+2)-12y)=0

We multiply parentheses

35y+12y-(25(3y+2)-12y)-14+36=0



We calculate terms in parentheses: -(25(3y+2)-12y), so:

25(3y+2)-12y

We add all the numbers together, and all the variables

-12y+25(3y+2)

We multiply parentheses

-12y+75y+50

We add all the numbers together, and all the variables

63y+50

Back to the equation:

-(63y+50)



We add all the numbers together, and all the variables

47y-(63y+50)+22=0

We get rid of parentheses

47y-63y-50+22=0

We add all the numbers together, and all the variables

-16y-28=0

We move all terms containing y to the left, all other terms to the right

-16y=28

y=28/-16

y=-1+3/4

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