7(5x+5)=-5(x+4)+55+40x

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Solution for 7(5x+5)=-5(x+4)+55+40x equation: 



7(5x+5)=-5(x+4)+55+40x

We move all terms to the left:

7(5x+5)-(-5(x+4)+55+40x)=0

We multiply parentheses

35x-(-5(x+4)+55+40x)+35=0



We calculate terms in parentheses: -(-5(x+4)+55+40x), so:

-5(x+4)+55+40x

determiningTheFunctionDomain
-5(x+4)+40x+55

We add all the numbers together, and all the variables

40x-5(x+4)+55

We multiply parentheses

40x-5x-20+55

We add all the numbers together, and all the variables

35x+35

Back to the equation:

-(35x+35)



We get rid of parentheses

35x-35x-35+35=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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