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7(5x+3)=2(5x+34)
We move all terms to the left:
7(5x+3)-(2(5x+34))=0
We multiply parentheses
35x-(2(5x+34))+21=0
We calculate terms in parentheses: -(2(5x+34)), so:We get rid of parentheses
2(5x+34)
We multiply parentheses
10x+68
Back to the equation:
-(10x+68)
35x-10x-68+21=0
We add all the numbers together, and all the variables
25x-47=0
We move all terms containing x to the left, all other terms to the right
25x=47
x=47/25
x=1+22/25
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