7(5k-8)-20=11(2k-3)+3k

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Solution for 7(5k-8)-20=11(2k-3)+3k equation: 



7(5k-8)-20=11(2k-3)+3k

We move all terms to the left:

7(5k-8)-20-(11(2k-3)+3k)=0

We multiply parentheses

35k-(11(2k-3)+3k)-56-20=0



We calculate terms in parentheses: -(11(2k-3)+3k), so:

11(2k-3)+3k

We add all the numbers together, and all the variables

3k+11(2k-3)

We multiply parentheses

3k+22k-33

We add all the numbers together, and all the variables

25k-33

Back to the equation:

-(25k-33)



We add all the numbers together, and all the variables

35k-(25k-33)-76=0

We get rid of parentheses

35k-25k+33-76=0

We add all the numbers together, and all the variables

10k-43=0

We move all terms containing k to the left, all other terms to the right

10k=43

k=43/10

k=4+3/10

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