7(5b+2)+4(b+3)=26

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Solution for 7(5b+2)+4(b+3)=26 equation: 



7(5b+2)+4(b+3)=26

We move all terms to the left:

7(5b+2)+4(b+3)-(26)=0

We multiply parentheses

35b+4b+14+12-26=0

We add all the numbers together, and all the variables

39b=0

b=0/39

b=0

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