7(5-c)=8(c-4)

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Solution for 7(5-c)=8(c-4) equation: 



7(5-c)=8(c-4)

We move all terms to the left:

7(5-c)-(8(c-4))=0

We add all the numbers together, and all the variables

7(-1c+5)-(8(c-4))=0

We multiply parentheses

-7c-(8(c-4))+35=0



We calculate terms in parentheses: -(8(c-4)), so:

8(c-4)

We multiply parentheses

8c-32

Back to the equation:

-(8c-32)



We get rid of parentheses

-7c-8c+32+35=0

We add all the numbers together, and all the variables

-15c+67=0

We move all terms containing c to the left, all other terms to the right

-15c=-67

c=-67/-15

c=4+7/15

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