7(4x-2)=7(1+7x)

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Solution for 7(4x-2)=7(1+7x) equation: 



7(4x-2)=7(1+7x)

We move all terms to the left:

7(4x-2)-(7(1+7x))=0

We add all the numbers together, and all the variables

7(4x-2)-(7(7x+1))=0

We multiply parentheses

28x-(7(7x+1))-14=0



We calculate terms in parentheses: -(7(7x+1)), so:

7(7x+1)

We multiply parentheses

49x+7

Back to the equation:

-(49x+7)



We get rid of parentheses

28x-49x-7-14=0

We add all the numbers together, and all the variables

-21x-21=0

We move all terms containing x to the left, all other terms to the right

-21x=21

x=21/-21

x=-1

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