7(4x+3)=7(2x-8)=

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Solution for 7(4x+3)=7(2x-8)= equation: 



7(4x+3)=7(2x-8)=

We move all terms to the left:

7(4x+3)-(7(2x-8))=0

We multiply parentheses

28x-(7(2x-8))+21=0



We calculate terms in parentheses: -(7(2x-8)), so:

7(2x-8)

We multiply parentheses

14x-56

Back to the equation:

-(14x-56)



We get rid of parentheses

28x-14x+56+21=0

We add all the numbers together, and all the variables

14x+77=0

We move all terms containing x to the left, all other terms to the right

14x=-77

x=-77/14

x=-5+1/2

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