7(4x+1)=13(3x-2)

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Solution for 7(4x+1)=13(3x-2) equation:


Simplifying
7(4x + 1) = 13(3x + -2)

Reorder the terms:
7(1 + 4x) = 13(3x + -2)
(1 * 7 + 4x * 7) = 13(3x + -2)
(7 + 28x) = 13(3x + -2)

Reorder the terms:
7 + 28x = 13(-2 + 3x)
7 + 28x = (-2 * 13 + 3x * 13)
7 + 28x = (-26 + 39x)

Solving
7 + 28x = -26 + 39x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-39x' to each side of the equation.
7 + 28x + -39x = -26 + 39x + -39x

Combine like terms: 28x + -39x = -11x
7 + -11x = -26 + 39x + -39x

Combine like terms: 39x + -39x = 0
7 + -11x = -26 + 0
7 + -11x = -26

Add '-7' to each side of the equation.
7 + -7 + -11x = -26 + -7

Combine like terms: 7 + -7 = 0
0 + -11x = -26 + -7
-11x = -26 + -7

Combine like terms: -26 + -7 = -33
-11x = -33

Divide each side by '-11'.
x = 3

Simplifying
x = 3

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