7(4v-6)=8v-22

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Solution for 7(4v-6)=8v-22 equation: 



7(4v-6)=8v-22

We move all terms to the left:

7(4v-6)-(8v-22)=0

We multiply parentheses

28v-(8v-22)-42=0

We get rid of parentheses

28v-8v+22-42=0

We add all the numbers together, and all the variables

20v-20=0

We move all terms containing v to the left, all other terms to the right

20v=20

v=20/20

v=1

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