7(4q-10)+3q=-10q+5

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Solution for 7(4q-10)+3q=-10q+5 equation: 



7(4q-10)+3q=-10q+5

We move all terms to the left:

7(4q-10)+3q-(-10q+5)=0

We add all the numbers together, and all the variables

3q+7(4q-10)-(-10q+5)=0

We multiply parentheses

3q+28q-(-10q+5)-70=0

We get rid of parentheses

3q+28q+10q-5-70=0

We add all the numbers together, and all the variables

41q-75=0

We move all terms containing q to the left, all other terms to the right

41q=75

q=75/41

q=1+34/41

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