7(46x+4)=32(48-6x)

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Solution for 7(46x+4)=32(48-6x) equation: 



7(46x+4)=32(48-6x)

We move all terms to the left:

7(46x+4)-(32(48-6x))=0

We add all the numbers together, and all the variables

7(46x+4)-(32(-6x+48))=0

We multiply parentheses

322x-(32(-6x+48))+28=0



We calculate terms in parentheses: -(32(-6x+48)), so:

32(-6x+48)

We multiply parentheses

-192x+1536

Back to the equation:

-(-192x+1536)



We get rid of parentheses

322x+192x-1536+28=0

We add all the numbers together, and all the variables

514x-1508=0

We move all terms containing x to the left, all other terms to the right

514x=1508

x=1508/514

x=2+240/257

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