7(4-x+8)=2(3x-4)

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Solution for 7(4-x+8)=2(3x-4) equation: 



7(4-x+8)=2(3x-4)

We move all terms to the left:

7(4-x+8)-(2(3x-4))=0

We add all the numbers together, and all the variables

7(-1x+12)-(2(3x-4))=0

We multiply parentheses

-7x-(2(3x-4))+84=0



We calculate terms in parentheses: -(2(3x-4)), so:

2(3x-4)

We multiply parentheses

6x-8

Back to the equation:

-(6x-8)



We get rid of parentheses

-7x-6x+8+84=0

We add all the numbers together, and all the variables

-13x+92=0

We move all terms containing x to the left, all other terms to the right

-13x=-92

x=-92/-13

x=7+1/13

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