7(4-4x)+1=141

Simple and best practice solution for 7(4-4x)+1=141 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 7(4-4x)+1=141 equation:


Simplifying
7(4 + -4x) + 1 = 141
(4 * 7 + -4x * 7) + 1 = 141
(28 + -28x) + 1 = 141

Reorder the terms:
28 + 1 + -28x = 141

Combine like terms: 28 + 1 = 29
29 + -28x = 141

Solving
29 + -28x = 141

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-29' to each side of the equation.
29 + -29 + -28x = 141 + -29

Combine like terms: 29 + -29 = 0
0 + -28x = 141 + -29
-28x = 141 + -29

Combine like terms: 141 + -29 = 112
-28x = 112

Divide each side by '-28'.
x = -4

Simplifying
x = -4

See similar equations:

| (-35)*z=-210 | | 11y+35=103-y | | 5y+40=103-y | | 23=f+5 | | 5y+41=103-y | | 6=13-m | | 26=f+21 | | 16=8k | | 20=s+13 | | cos(20+10x)=0.6 | | 5y+3(2y)+35=103-y | | 8+8=10 | | x+155=180 | | -40=-8p | | x-155=180 | | 20=v+16 | | 155x=180 | | 27/60=9/x | | 7=h-8 | | x-40=115 | | x-40+115=180 | | cos^2(5x)xsin^2(5x)=0 | | 6j-9=-2j-9 | | H-33=23 | | 2y-26=-3(y-3) | | 7n=15+2n | | 3-2(9+a)=a-6 | | 17/8=v/4 | | 3(4x+4)=-3(3x-5)-4x | | F(3)=(3-6)(3+1)(3-3) | | 49=3x+4x | | 16v-8v=48 |

Equations solver categories