7(4-(5+4x))-4x=-9+2(1-16x)

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Solution for 7(4-(5+4x))-4x=-9+2(1-16x) equation: 



7(4-(5+4x))-4x=-9+2(1-16x)

We move all terms to the left:

7(4-(5+4x))-4x-(-9+2(1-16x))=0

We add all the numbers together, and all the variables

7(4-(4x+5))-4x-(-9+2(-16x+1))=0

We add all the numbers together, and all the variables

-4x+7(4-(4x+5))-(-9+2(-16x+1))=0



We calculate terms in parentheses: -(-9+2(-16x+1)), so:

-9+2(-16x+1)

determiningTheFunctionDomain
2(-16x+1)-9

We multiply parentheses

-32x+2-9

We add all the numbers together, and all the variables

-32x-7

Back to the equation:

-(-32x-7)



We get rid of parentheses

-4x+7(4-(4x+5))+32x+7=0

We add all the numbers together, and all the variables

28x+7(4-(4x+5))+7=0

We move all terms containing x to the left, all other terms to the right

28x+7(4-(4x+5))=-7

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