7(4+y)=6(1+y)

Solution for 7(4+y)=6(1+y) equation:

7(4+y)=6(1+y)

We move all terms to the left:

7(4+y)-(6(1+y))=0

We add all the numbers together, and all the variables

7(y+4)-(6(y+1))=0

We multiply parentheses

7y-(6(y+1))+28=0


We calculate terms in parentheses: -(6(y+1)), so:

6(y+1)

We multiply parentheses

6y+6

Back to the equation:

-(6y+6)


We get rid of parentheses

7y-6y-6+28=0

We add all the numbers together, and all the variables

y+22=0

We move all terms containing y to the left, all other terms to the right

y=-22