7(3z+2)=21z+14

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Solution for 7(3z+2)=21z+14 equation:


Simplifying
7(3z + 2) = 21z + 14

Reorder the terms:
7(2 + 3z) = 21z + 14
(2 * 7 + 3z * 7) = 21z + 14
(14 + 21z) = 21z + 14

Reorder the terms:
14 + 21z = 14 + 21z

Add '-14' to each side of the equation.
14 + -14 + 21z = 14 + -14 + 21z

Combine like terms: 14 + -14 = 0
0 + 21z = 14 + -14 + 21z
21z = 14 + -14 + 21z

Combine like terms: 14 + -14 = 0
21z = 0 + 21z
21z = 21z

Add '-21z' to each side of the equation.
21z + -21z = 21z + -21z

Combine like terms: 21z + -21z = 0
0 = 21z + -21z

Combine like terms: 21z + -21z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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