7(3y/15)=6(y/10)

Solution for 7(3y/15)=6(y/10) equation:

7(3y/15)=6(y/10)

We move all terms to the left:

7(3y/15)-(6(y/10))=0

We add all the numbers together, and all the variables

7(+3y/15)-(6(+y/10))=0

We multiply parentheses

21y-(6(+y/10))=0

We multiply all the terms by the denominator


21y*10))-(6(+y=0

We add all the numbers together, and all the variables

y+21y*10))-(6(=0

Wy multiply elements

210y^2+y=0

a = 210; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·210·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*210}=\frac{-2}{420}
=-1/210
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*210}=\frac{0}{420}
=0
$