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7(3x-5)=3(x+5)
We move all terms to the left:
7(3x-5)-(3(x+5))=0
We multiply parentheses
21x-(3(x+5))-35=0
We calculate terms in parentheses: -(3(x+5)), so:We get rid of parentheses
3(x+5)
We multiply parentheses
3x+15
Back to the equation:
-(3x+15)
21x-3x-15-35=0
We add all the numbers together, and all the variables
18x-50=0
We move all terms containing x to the left, all other terms to the right
18x=50
x=50/18
x=2+7/9
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